29x-x^2=204

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Solution for 29x-x^2=204 equation:



29x-x^2=204
We move all terms to the left:
29x-x^2-(204)=0
We add all the numbers together, and all the variables
-1x^2+29x-204=0
a = -1; b = 29; c = -204;
Δ = b2-4ac
Δ = 292-4·(-1)·(-204)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-5}{2*-1}=\frac{-34}{-2} =+17 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+5}{2*-1}=\frac{-24}{-2} =+12 $

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